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sashaice [31]
3 years ago
12

1. IN hex: a. Convert 1000 to hex; b. Add DEF to CBA.

Mathematics
1 answer:
juin [17]3 years ago
3 0

Answer:

a) (1000)_2=(8)_{10}

b) DEF+ CBA =1AA9      

Step-by-step explanation:

To find : a) Convert 1000 to hex

b) Add DEF to CBA.

Solution :

a) Convert 1000 to hex

First we convert base 2 into base 10,

i.e. (1000)_2=(1\times 2^3+0\times 2^2+0\times 2^1+0\times 2^0)_{10}

(1000)_2=(8+0+0+0)_{10}

(1000)_2=(8)_{10}

Since, the digit 8 is same in both decimal and hexadecimal.

So, (1000)_2=(8)_{10}

b) Add DEF to CBA.

According to binary system,

A=10 , B=11 , C=12, D=13, E=14, F=15

Adding them with the following steps,

F=15 and A=10

So, 15+10=25

25 in hexadecimal is 19.

We put 9 at first place and forward 1 as a carry.

F=14 and B=11

So, 1+E+B=1+14+11=26

26 in hexadecimal is 1A.

We put A at second place and forward 1 as a carry.

D=13 and C=12

So, 1+D+C=1+13+12=26

26 in hexadecimal is 1A.

We put A at third place and forward 1 as a carry.

 D E F

+C B A

-------------

1 A A 9

Therefore, DEF+ CBA =1AA9

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Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
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Given:

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The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

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y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

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y=-\dfrac{4}{7}x-12+2

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Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste
Volgvan

Answer:

a) The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

<u><em>Step(ii)</em></u>:-

<em>Null Hypothesis H₀</em> : μ >10

<em>Alternative Hypothesis</em> : H₁ : μ < 10

Test statistic

                 t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }

               t =  5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄  = 2.572

The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

<u><em>p- value</em></u> :

p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

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