Four consecutive integers... n, n+1, n+2, n+3.
The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.
n(n+3)=2n(n+3)-4 perform indicated multiplications...
n^2+3n=2n^2+6n-4 subtract n^2 from both sides
3n=n^2+6n-4 subtract 3n from both sides
n^2+3n-4=0 factor
n^2-n+4n-4=0
n(n-1)+4(n-1)=0
(n+4)(n-1)=0, and since n>0
n=1
So the four numbers are 1, 2, 3, 4
check...
1(4)=2(1)4-4
4=8-4
4=4
Answer:
b
Step-by-step explanation:
Answer:
hmm this is tough but i would have to say good evening
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
Given that
Current count of pushups = 8
Number of increase in pushups each day = 2
The desired pushup goal on daily basis = 30
Days require = x= ?
as we can conclude the number of pushups would increase by following sequence
8, 10, 12, 14, 16, ......30
Now as we can be the number of pushups by a constant number each day it means this sequence is arithmetic.
First term of our sequence is X1 and the final term is Xn, and the difference between two consecutive terms (Common Difference) is 2.
So
X1 = 8
Xn = 30
d = 2
Using the formula of nth term for arithmetic sequence
Xn = X1 + (n-1)d
Substituting the values
30 = 8 + (n-1)2
30-8 = (n-1)2
22 = 2n -2
22+2 = 2n
2n = 24
n = 24/2
n = 12
So, it means on the 12th day he will have to do 30 pushups if he starts from 8 and increase 2 pushups each day.
Answer: 4611/1000
Move the decimal place until it is a whole number and if you moved it 3 places the denominator will have that much zeros