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dem82 [27]
3 years ago
9

i can't figure out how to solve this math problem. Given the function f(x)=1/x+9, calculate the following values: (f(a+h)-f(a))/

h
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
68 ?2000000000.888888
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Vvvvvvv help me plzzzzzzzzzzzzzzz
Ivahew [28]

Answer:

the answer is 0

Step-by-step explanation:

she had -27 in her bank the she added  27

8 0
3 years ago
Find the vertex of y=-x^2+6x-12
Debora [2.8K]
You find the x coordinates using x = -b/2a  = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)
8 0
3 years ago
Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average. Margie wants to k
mojhsa [17]

Answer:

0.6804

Step-by-step explanation:

Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.

Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3

Required probability

= Prob that atleast four of 6 times good serve

=P(X\geq 4)

=P(x=4,5 or 6)\\=1-F(3)\\=0.6804

Formula used:

P(X=r) =6Cr (\frac{2}{3}^r )(\frac{1}{3}^{6-r}  )

7 0
3 years ago
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yuradex [85]

Answer:

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8 0
3 years ago
The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli
stiks02 [169]
The first line through points (-3, 0) and (-4, -1) is the orange line.

The second line, through (1, 1) and (2, -1) is the purple line.

Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.

Both lines are included, since they are solid lines.



The equation of the first line can be found as follows:

the slope is \frac{0-(-1)}{-3-(-4)}=\frac{1}{1}=1, thus, the equation is:
y-0=1(x-(-4))\\\\y=x+4


The equation of the second line can be found as follows:

the slope is \frac{1-(-1)}{1-2}= \frac{2}{-1}=-2, 

thus the equation of the second line is :


y-1=-2(x-1)\\\\y-1=-2x+2\\\\y=-2x+3


We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines, 

so we write the inequalities so that they do not hold for (0, 4)


line 1:

y≥x+4

4≥0+4=4 is true, so we change the sign and write : y≤x+4


similarly, line 2:

y≤-2x+3

4≤-2*0+3=3, which is not true, so we have the correct direction.


Note that since the lines were solid, we include the equality case:


Answer: 

the shaded region is the solution to the system of inequalities:

i) y≤x+4
ii) y≤-2x+3

3 0
3 years ago
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