Not sure I'm right but:
If the bar weighs 9.25 ounces and 65% of the bar is gold, you'd do 65% of 9.25. So the answer would be <span>65% of 9.25= 6.0125</span>
Answer:
I think it might be data and range
Step-by-step explanation:
the answer is at the top
Answer: Required expression:
Result: 
Step-by-step explanation:
Given phrase: 
Required expression:
['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence,
Answer:
To find the scale factor of the enlargement, compare the distance between a pair of corresponding points from both shapes.
<u>Shape K</u>
A = (4, 7)
B = (7, 7)
C = (7, 4)
D = (5, 5)
Horizontal distance between A (4, 7) and B (7, 7) = 3 units
<u>Shape L</u>
A' = (0, 11)
B' = (9, 11)
C' = (9, 2)
D' = (3, 5)
Horizontal distance between A' (0, 11) and B' (9, 11) = 9 units
9 ÷ 3 = 3
Therefore, Shape L is an enlargement of Shape K by scale factor 3.
To find the center of dilation (enlargement), draw two lines through 2 corresponding points (e.g. A and A', B and B') - the point of intersection of these lines is the center of dilation.
Therefore, the center of enlargement is (6, 5) (refer to the second attached image).