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Cloud [144]
3 years ago
11

PLZZ HELLLPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

please send the question thnx

Step-by-step explanation:

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A national organization has been working with utilities throughout the nation to find sites for large wind machines that generat
kozerog [31]

Answer:

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.

Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

8 0
3 years ago
Please Solve<br><br> 6(x + 4) = 30
lianna [129]

Answer: x=1

Step-by-step explanation: 6x+24=30

6x=6

x=1

6 0
3 years ago
Read 2 more answers
Suppose U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} is the universal set and G = {1, 2, 3, 4, 5, 6, 7}. What is G?
Nesterboy [21]
Your posted question defines G, then asks what G is.
G is the set in the definition you gave.

G = {1, 2, 3, 4, 5, 6, 7}

_____
Perhaps you want to know the complement of G. That is all the elements of U that are not in G.

G' = {8, 9, 10}
3 0
2 years ago
100m world record was completed at an average speed of 37.6 km/h. work out this speed in meters per second?
pickupchik [31]

Step-by-step explanation:

1 km = 1000 m

1 hour = 3600 s

so,

37.6 km = 37,600 m (still per hour or per 3600 s).

in 1 second now that is

37600/3600 = 10.44444444... m/s

4 0
1 year ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
3 years ago
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