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Cloud [144]
3 years ago
11

PLZZ HELLLPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

please send the question thnx

Step-by-step explanation:

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I need help With this cuestión
DiKsa [7]
You are correct. 8 divided by 24 is 3. :)
3 0
3 years ago
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The two dice are rolled. what is the theoretical chance that they land to form a sum of 11?
Rufina [12.5K]

Answer:

Propability of getting either sum is 2/9

Step-by-step explanation:

Well, we know that there are 36 total arrangements of the two six sided die. So we have a possibility of 3,4 and 4,3. Likewise, we have a possibility of 5,2 and 2,5. We also have a possibility of 1,6 and 6,1. That takes care of the probability That you get two die that add up to 7. Now for 11, you have 5,6 and 6,5. So since you asked for the probability of getting either or, you add all the probabilities, which is 6/36+2/36=8/36=2/9. So the probability of getting either sum is 2/9.

5 0
3 years ago
The radius of a sphere is 3 inches. Which represents the volume of the sphere?
Phantasy [73]

Answer:

the third one is your answer

Step-by-step explanation:

6 0
3 years ago
(a) Show that the volume of a metal sphere of radius 15 cm is 14140 cm”, correct to 4 significant
Sladkaya [172]

Answer:

a) The volume of the sphere is approximately 14,137.16694 which is 14,140 cm³ correct to 4 significant figures

b) The volume of water required to fill the tank is approximately 103,670 cm³

Step-by-step explanation:

a) In the question, the radius of the sphere, r = 15 cm

The formula for the volume, 'V', of a sphere is given as follows;

V = \dfrac{4}{3} \times \pi \times r^3

Where;

r = The radius of the the sphere

V = The volume of the sphere

Plugging in the value for the radius, 'r', of the sphere, in the equation for, 'V', we get;

V = \dfrac{4}{3} \times \pi \times 15^3 \approx = 14,137.16694

Therefore;

The volume of the sphere to 4 significant figures is V ≈ 14,140 cm³

b) The parameters of the cylindrical tank are;

The height of the cylindrical tank, h = 60 cm

The radius of the cylindrical tank, r = 25 cm

The volume of a cylinder, V = π·r²·h

∴ The volume of the cylindrical tank without water, 'V_t', is given as follows;

V_t = π × (25 cm)² × 60 cm ≈ 117809.72451 cm³

The volume of water, V_{water}, required to fill the tank with the sphere of volume 'V' placed inside is given as follows

V_t = V + V_{water}

∴ V_{water} = V_t - V

From which we get;

V_{water} ≈ 117809.72451 cm³ - 14,140 cm³ = 103,669.72451 cm³ ≈ 103,670 cm³

The volume of water required to fill the tank, V_{water} ≈ 103,670 cm³.

8 0
3 years ago
If y varies directly and y is 12 when x is 1.2 what is the constant of variation for this relation
sergij07 [2.7K]

Answer:

10

Step-by-step explanation:

The constant of variation would be 12 / 1.2 = 10.

7 0
3 years ago
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