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vodomira [7]
3 years ago
10

What is 28/25 in simplest form

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0
This is already in simplest form
Dvinal [7]3 years ago
4 0
It's already in the lowest form, but you can write 1 3/25
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To solve the equation: 14 = t +72 This is a(n)
krek1111 [17]

Answer:

t=-58

Step-by-step explanation:

14=t+72\\14-72=t+72-72\\-58=t

3 0
2 years ago
Use the net to find the size of the base and the height of each triangular face of this square pyramid.
antiseptic1488 [7]
The base is 16 and height of each triangle is 2
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The lengths of the sides of a triangle are in the extended ratio 8 : 9 : 10. The perimeter of the triangle is 108cm. What are th
belka [17]

Answer:

32, 36, 40

Step-by-step explanation:

8x + 9x + 10x = 108

27x = 108

x = 4

4 × 8 = 32 - 1st side

4 × 9 = 36 - 2nd side

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3 0
2 years ago
Find x<br><br> show steps too please<br><br> will give brainliest
9966 [12]

Hello from MrBillDoesMath!

Answer:   x = 7/10

Discussion:

To eliminate fractions multiply each side by 10:

10 ( 9/5x - 2/5 )  = 10 * ( 8x +3)/10      or

10 * ( 9/5)x - 10 *(2/5)  =   8x + 3  or

9 *2 x - 2*2 = 8x +3   or

18x - 4 = 8x + 3.  Subtract 8x for each side:

18x - 8x - 4 = (8x - 8x) + 3 or

10x -4 =  0x + 3 or

10x -4 = 3 or

10x = 7

x = 7/10




Thank you,

MrB

7 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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