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3 years ago

What is the standard form of the equation of the circle x^2 - 2x + y^2 - 8y + 8 = 0?

Mathematics

1 answer:

lesantik [10]3 years ago

4 0

Answer:

Step-by-step explanation:

Begin by grouping the x terms and the y terms together and separating the constants out.

$(x^2-2x)+(y^2-8y)=-8$

Now we'll complete the square on those x and y terms. Take half the linear term of each, square it, and add it to both sides. Our linear x term is 2, half of 2 is 1 and 1 squared is 1, so we add that in. Likewise, half the linear y term (which is 8) is 4, and 4 squared is 16, so we add that in, too. Like this:

$(x^2-2x+1)+(y^2-8x+16)=-8+1+16$

Doing this gives us the perfect square binomials for each of the x and y terms, and then gives us the radius on the right:

$(x-1)^2+(y-4)^2=9$

This is a circle with a center of (1, 4) and a radius of 3.

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At the end of the Crimson Comet's soccer season, Coach Billy hosted a party for the players. He had 24 players on his team and o

stealth61 [152]

Answer:

HUH. OH 40

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A parallelogram has a length of 6 centimeters and a width of 4.5 centimeters. This parallelogram is dilated by a scale factor of

Arada [10]

Scale factor is given by:
(length of larger figure)/(length of smaller figure)=(width of larger figure)/(width of the smaller figure)=3.4
The length of the larger figure will be given by:
length=(scale factor)*(length of smaller figure)
=3.4*6=20.4 cm
width of the larger figure will be given by:
width=(scale factor)*(width of smaller figure)
=3.4*4.5
=15.3 cm
Therefore the dimension of the new parallelogram will be 20.4 cm by 15.3 cm

3 0

4 years ago

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

$t=\frac{-35\pm \sqrt{1225+25600}}{-32}$

$\implies t\approx -4.02\text{ or }t\approx 6.21$

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0

3 years ago

Which graph represents the equation 12 = 32 + 4y? Explain how you know.

sergeinik [125]

What graph?
BTW the answer to that equation is: x=5
12=32+4y
12-12= 0 (cancels out)
32-12= 20
20 divided by 4= 5
Therefore, x=5

6 0

3 years ago

It’s not 0.615 , or 0.75 or the one shown in the picture

Dafna1 [17]

$2.40714$

1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5

$\begin{gathered} a^3\div b^2+c^3 \\ (4.9)^3\div(-7)^2+(-0.5)^3= \\ \frac{4.9^3}{\left(-7\right)^2+\left(-0.5\right)^3} \\ \\ \frac{4.9^3}{48.875} \\ \\ \frac{117.649}{48.875} \\ \\ 2.40714 \end{gathered}$

Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.

6 0

1 year ago