Write the equation of a line that is perpendicular to y = 5 y=5y, equals, 5 and that passes through the point ( − 7 , − 5 ) (−7,
2 answers:
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Option C:
5, 1, 7
Solution:
Given equation:
y = |3x + 1|
In the chart, x values are given as –2, 0, 2.
To find the value of y for the corresponding x given.
Substitute x = –2 in the equation of y.
y = |3(–2) + 1|
= |–6 + 1|
= |–5| (Absolute value of a negative number is positive)
y = 5
Substitute x = 0 in the equation of y.
y = |3(0) + 1|
= |0 + 1|
= |1|
y = 1
Substitute x = 2 in the equation of y.
y = |3(2) + 1|
= |6 + 1|
= |7| (Absolute value of a negative number is positive)
y = 7
Option C is the correct answer.
The values of y are 5, 1, 7.
The answer image of the table is attached below.
