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2 years ago

Jill's fish weighs 8 times as much as her parakeet. Together, the pets weigh 63 ounces. How much does the fish weigh?

2 answers:

7 0

Let $x$ be the weight of her parakeet. From this, we know that her fish weighs $8x$ .

$8x + x = 63$
$9x = 63$
$x = 7$

Her fish weighs 7 x 8 ounces = 56 ounces.

Ipatiy [6.2K]2 years ago

7 0

Let x =the weight of the parakeet. 8x=weight of the fish. x+8x=63 <-weight of fish and parakeet together equals 63 ounces. SOLVE FOR X. 9x=63. /9 /9 x=7 <-- parakeet weighs 7 ounces. 8x= 8(7). 8x7= 56. the fish weighs 56 ounces.

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3 years ago

An opera house has a seating capacity of 872 people with each ticket costing 50 Rupees .If the opera house is running for 15 day

Nataly_w [17]

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2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

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3 years ago