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4 years ago

Can a triangle be formed with the side lenths of 8 cm ,4cm 12cm

Mathematics

2 answers:

kaheart [24]4 years ago

3 0

Yes it can, but your triangle is going to look a little lopsided.

lesya692 [45]4 years ago

3 0

To actually have a triangle, the two SMALLEST sides, have to be BIGGER than the biggest side when added up.

So, 8+4=12

12=12.

Thus, you can't make a triangle, because the two smallest sides aren't bigger than the biggest side.

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A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9^

MrRa [10]

Correct question is;

A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²

(a) Determine the expression for the instantaneous rate of change in height at time t.

(b) Determine ' (2) What does ' (2) represent?

Answer:

A) '() = 24 − 9.8

B) '(2) = 4.4 m/s

It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

Step-by-step explanation:

We are given the function to represent the height as;

() = 24 − 4.9²

A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;

'() = 24 − 9.8

B) '(2) = 24 - 9.8(2)

'(2) = 4.4 m/s

This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

7 0

3 years ago

8i + 12 + 24j<br> Factor the expression

GalinKa [24]

Answer:

8*1+12+24*1

Step-by-step explanation:

3 0

3 years ago

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Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago

Please answer this correctly

Nana76 [90]

20% of the students chose a cupcake = 20 / 100: Shade 20 squares.

20 / 100 = x / 55

100x = 1100

x = 11 students who chose a cupcake

Hope this helps!! :)

8 0

3 years ago

Mind lending a hand here?

motikmotik

Answer: B

Step-by-step explanation: 75 + the amount of money she still needs is equal to or greater than (atleast) 200. hope this helps

7 0

3 years ago

Read 2 more answers