Answer:
Step-by-step explanation:
Let the first term is a and common difference is d.
<u>The nth term is:</u>
<u>We have:</u>
<u>The difference of these terms is:</u>
- (a + 8d) - (a + 5d) = 16 - 15
- 3d = 1
- d = 1/3
<u>Then the first term is:</u>
- a + 5*1/3 = 15
- a = 15 - 5/3 = 13 1/3
<u>The nth term equation is:</u>
- aₙ = 13 1/3 + 1/3(n - 1) = 1/3n + 13
<u>If the nth term is 22, find n:</u>
- 1/3n + 13 = 22
- 1/3n = 22 - 13
- 1/3n = 9
- n = 9*3
- n = 27
The first thing we are going to do is rewrite the expression correctly.
We have:
root (27x ^ 12 / 300x ^ 8)
Rewriting:
root ((27/300) * (x ^ 12 / x ^ 8))
root ((9/100) * (x ^ (12-8)))
root ((9/100) * (x ^ (4)))
root ((9/100) * (x ^ (4)))
3 * x ^ 2 * root ((1/100)
(3 * x ^ 2) / 10
(3/10) * (x ^ 2)
Answer:
(3/10) * (x ^ 2)
14.9682539683 Your welcome have a good day!
No because a 2 digit divisor always has less digits than a 3 digit divisor
Answer:
120
Step-by-step explanation:
First, you have to calculate the money that Seth would spent if he goes to 30 movies if his father gets the summer movie pass by adding up the cost of the pass plus the result of multiplying the cost per movie with the pass for the number of movies:
30+(3*30)=30+90=120
Second, you need to calculate the money that Seth would spent if he goes to 30 movies without the pass by multiplying the normal price per movie for the number of movies:
8*30=240
Third, you need to find the difference between both costs:
240-120=120
According to this, the answer is that if Seth plans to go to 30 movies this summer, he would save 120.
