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madreJ [45]
4 years ago
10

mark as brainliest!!!! A flare was launched straight up from the ground with an initial velocity of 176ft/s and returned to the

ground after 11 s. The height of the flare t seconds after launch is modeled by the function f(t)=−16t2+176t . What is the maximum height of the flare, in feet?
Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
7 0
I think 484 is the answer because, 0=t(-16t+176)  x=0 and  x=11.To get the add up the x intercepts and divide by 2 you should get that x=5.5.
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2. Apple Strudle muffins
Liono4ka [1.6K]

Answer:

Since there are 14 people who will eat 2 muffins each, you will need to make 28 muffins. To get this many muffins you will have to multiply the recipe by 2 1/3. Multiply each ingredient by 2 1/3 to make enough muffins

Step-by-step explanation:

6 0
4 years ago
6=1-2n+5 can you please solve it
stepan [7]

Answer:

n = 0

Step-by-step explanation:

6 = 1 - 2n + 5

6 = 6 -2n

0 = -2n

n = 0

3 0
4 years ago
Read 2 more answers
Please HELP! How do I set the combination problem to solve this... Ten students ask to visit a college admissions counselor. Eac
solniwko [45]

Answer:

30240

Step-by-step explanation:

There are 10 possibilities for the first time slot.

After that, there are 9 possibilities for the second time slot.

So on and so forth.

The number of ways five time slots can be assigned is:

10×9×8×7×6 = 30240

Or, using permutation notation, ₁₀P₅.

4 0
4 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
Select the correct answer
Lilit [14]

Answer: 0.32

Step-by-step explanation:

3 0
3 years ago
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