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3 years ago

Help please? its an exam

Mathematics

1 answer:

poizon [28]3 years ago

7 0

Answer:

Option 2

Step-by-step explanation:

In ΔABC,

AD is a median and point M is the point of concurrence of all medians.

Therefore, point M is a centroid of the triangle.

And M will divide line AD in the ratio of 1 : 2 (Ratio of AM : MD)

Since, length of MD = 2 cm

Therefore, length of AM = 4 cm

Total length of AD = AM + MD

= 2 + 4

= 6

Option 2 will be the answer.

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Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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3 years ago

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