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Anarel [89]
3 years ago
9

What is transferred by a water wave ?

Mathematics
2 answers:
Greeley [361]3 years ago
7 0
I believe it is C I hope this helped.
VikaD [51]3 years ago
4 0
The answer is C energy
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What is the area of the shape
Vera_Pavlovna [14]
To find the  area of a rhombus, the formula is d1(d2)/2
d1 is 4+4 or 8
d2 is 7+10 or 17
17(8)=136
136/2=68
8 0
3 years ago
Angle Q = 85° Determine angle O.
kkurt [141]

Answer:

∠O = 95°

Step-by-step explanation:

since ∠Q = 85°, arc NOP = 2(85°) = 170°

arc PQN = 360° - arc NOP

arc PQN = 360° - 170° = 190°

∠O = 1/2(arc PQN) = 1/2(190°) = 95°

4 0
3 years ago
Please help i wanna move to the next grade,10 points
AfilCa [17]

Answer:

C -1

Step-by-step explanation:

- 3x + 2 < 5

5 - 2 = 3

- 3x  \div  - 3

3 \div  - 3 =  - 1

x =  - 1

4 0
3 years ago
Identify the expression as a numerical expressionor a variable expression. For a variable expression, name the variable.
Karolina [17]

Answer:

Numerical expression

Step-by-step explanation:

This is a numerical expression since there is no unknown value. Both values being multiplied are numbers.

8 0
3 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
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