On a family trip, the baristas drive 110 miles in 2 hours. At this rate, how far would they drive in 7 hours

What is the measurement of the vertex angle of an isosceles triangle if one of its base angles measures 42 degree

kari74 [83]

Hello from MrBillDoesMath!

Answer:

96 degrees

Discussion:

The base angles of an isosceles triangle are equal and a triangle has 180 degrees. In our case this means that

42 + 42 + (measure of vertex angle) = 180

84 + (measure of vertex angle) = 180 => (subtract 84 from both sides)

84 - 84 + (measure of vertex angle) = 180- 84 =>

(measure of vertex angle) = 180- 84 = 96

Thank you,

MrB

3 0

3 years ago

For every 5 female teachers, there are 2 male teachers

gtnhenbr [62]

Answer:

so if there are 10 female teachers then there are 4 male teachers

Step-by-step explanation:

please mark brainliest

4 0

3 years ago

Please help for 50 points...

vaieri [72.5K]

Answer:

7. ○ ∆ACB ≅ ∆DFE

6. ○ $\displaystyle 43°$

5. ○ $\displaystyle ∠M ≅ ∠S$

4. ○ $\displaystyle octagon$

3. ○ $\displaystyle squares$

2. ○ $\displaystyle rhombus$

1. ○ $\displaystyle equilateral\:triangle$

Step-by-step explanation:

7. Everything is in correspondence with each other, so just follow the pattern in the order the they were originally.

6. All angles correspond with each other, so just follow the pattern.

5. All segments and angles correspond with each other, so just follow their patterns.

4. An octagon has eight sides, a triangle has three sides, a hexagon has six sides, and a pentagon has five sides. With this being stated, you have your answer.

3. In a previous lesson, we confirmed that all squares are rectangles because it is a quadrilateral with four right angles.

2. This is obviously a rhombus because it is a quadrilateral with four congruent angles and sides.

1. An EQUILATERAL TRIANGLE is a regular polygon because they have three congruent angles and sides.

I am joyous to assist you anytime.

4 0

3 years ago

Read 2 more answers

Write the equation of the line, given the y and x-intercepts:

kolezko [41]

Answer:

The answer to your question is: 161x + 17y - 391 = 0

Step-by-step explanation:

Data

y-intercept = 23 Get the points (0, 23)

x- intercept = 4.75 (4.75, 0)

4.75 = 17/4 (17/4, 0)

slope

m = (y2 - y1) / (x2 - x1)

m = (0 - 23) / (17/4 - 0)

m = -23 / 17/4

m = - 161 / 17

equation

(y - y1) = m (x - x1)

( y - 23) = -161 / 17 (x - 0)

y - 23 = -161/17 x

17(y - 23) = -161x

17y - 391 = -161x

161x + 17y - 391 = 0

7 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

2 years ago