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Dima020 [189]
4 years ago
6

If

c{3}{x+2} -\sqrt{x-3}" alt="f(x)=\frac{3}{x+2} -\sqrt{x-3}" align="absmiddle" class="latex-formula">, complete the following statement:
The domain for f(x) is all real numbers ___ than or equal to 3.
Mathematics
2 answers:
ira [324]4 years ago
7 0

Answer:

The domain for f(x) is all real numbers greater than or equal to 3.

Step-by-step explanation:

f(x)= \frac{3}{x+2} - \sqrt{x-3}

To solve the above equation, the value of x should be greater than or equal to 3, as we have the term \sqrt{x-3} and if value is less than 3, the term inside the square root will be negative and we cannot find the square root of negative numbers.

So, The domain for f(x) is all real numbers greater than or equal to 3.

kodGreya [7K]4 years ago
4 0

Answer:

"greater"

Step-by-step explanation:

The domain is the set of x values for which a function is defined.

When we have a square root is a function, we need to remember that square root can't be negative. Thus, anything under the root would need to be GREATER THAN or EQUAL to 0.

Thus

x - 3 ≥ 0

x ≥ 3

This is the constraint.

Thus

the _____ would be "greater"

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Marta_Voda [28]
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3 years ago
Please answer This question...​
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Answer:

(2) 4, 7, 9; 2, 5, 6; 1, 3, 8

Step-by-step explanation:

Let's group them based on how many lines they have inside the shape...

0 lines: 4, 7, 9

2 lines: 2, 5, 6

3 lines: 1, 3, 8

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2 years ago
10x +2y = 64
Musya8 [376]

Answer:

<h2>x = 4, y = 12 → (4, 12)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}10x+2y=64&\text{multiply both sides by 2}\\3x-4y=-36\end{array}\right\\\underline{+\left\{\begin{array}{ccc}20x+4y=128\\3x-4y=-36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad23x=92\qquad\text{divide both sides by 2}\\.\qquad x=4\\\\\text{put the value of x to the first equation:}\\\\10(4)+2y=64\\40+2y=64\qquad\text{subtract 40 from both sides}\\2y=24\qquad\text{divide both sides by 2}\\y=12

5 0
4 years ago
Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point) a 2 b 3 c All real numbers d No solution
sashaice [31]

The correct answer would be

C. All Real Numbers

8 0
3 years ago
It takes a hose 2 minutes to fill a rectangular aquarium 8 inches long, 9 inches wide, and 13 inches tall. How long will it take
nirvana33 [79]
To make it easier, you calculate the volume of the first aquarium.

1st aquarium:
V = L x W x H
V = 8 x 9 x 13
V = 72 x 13
V = 936 in.
Rate: 936 in./2 min.

Now that you've got the volume and rate of the first aquarium, you can find how many inches of the aquarium is filled within a minute, which is also known as the unit rate. To do that, you have to divide both the numerator and denominator by their least common multiple, which is 2. 936 divided by 2 is 468 and 2 divided by 2 is 1.
So the unit rate is 468 in./1 min. Now that you've got the unit rate, you can find out how long it'll take to fill the second aquarium up by finding its volume first.

2nd aquarium:
V = L x W x H
V = 21 x 29 x 30
V = 609 x 30
V 18,270 inches

Calculations:
Now, you divide 18,270 by 468 to find how many minutes it will take to fill up the second aquarium. 18,270 divided by 468 is about 39 (the answer wasn't exact, so I said "about").
 
2nd aquarium's rate:
18,270 in./39 min.

As a result, it'll take about 39 minutes to fill up an aquarium measuring 21 inches by 29 inches by 30 inches using the same hose. I really hope I helped and that you understood my explanation! :) If I didn't, I'm sorry. I tried. :(
7 0
3 years ago
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