Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
IQ scores of at least 130.81 are identified with the upper 2%.
Answer:
4y + 48 - 16x = 0 ~Solve for y~
4y = -48 + 16x
y = -12 + 4x
The slope is 4.
We'll use the point (1, 4) and m = 4.
Plug these into the equation: y - y1 = m(x - x1)
y - 4 = 4(x - 1)
y - 4 = 4x - 4
y = 4x
Just use the definitions and put them in order to explain the problem.m. for instance. why are angles a and b vertical angles? they are adjacent and they are supplementary.
Answer:
(x+6i)(x-6i)(x+1)
So the zeroes are 6i, -6i, -1
Step-by-step explanation:
Factor by grouping
h(x) = x^2(x+1) + 36(x+1)
h(x) = (x^2+36)(x+1)
Answer: SU, TU, ST is the right answer
Step-by-step explanation: In a triangle
The largest side and the largest angle are opposite to each other
The shortest side and the shortest angle are opposite to each other.
So using the above axioms we can observe the triangle.
The largest angle is m∠U = 80° so the side opposite to it is the largest i.e. ST is the largest
The smallest angle is m∠T = 25° so the shortest side is SU
The third side will be the middle side as the angle ∠S is greater than 25° and less than 80°
So the sides in order from least to greatest are: SU, TU, ST
