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3 years ago

The area of a square poster is 37 in.2. Find the length of one side of the poster to the nearest tenth of an inch.

Mathematics

1 answer:

mojhsa [17]3 years ago

7 0

Answer:

6.1 in

Step-by-step explanation:

√37=6.08276

6.1 in

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1. (5,8) m= 3<br> It wants me to write this in slope intercept form

ikadub [295]

Answer:

The answer is: y = 3x - 7

Step-by-step explanation:

Given point: (5, 8).

Slope m = 3

Use the point slope form and solve for y:

y - y1 = m(x - x1)

y - 8 = 3(x - 5)

y - 8 = 3x - 15

y = 3x - 15 + 8

y = 3x - 7

Proof:

f(x) = 3x - 7

f(5) = 3(5) - 7

= 15 - 7 = 8, giving (5, 8)

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uysha [10]

Answer:

Step-by-step explanation:

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3 years ago

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Rainbow [258]

I think the first on is A the second one D and the third one B

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4 years ago

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Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

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3 years ago

Evaluate f(x) = - 3x - 4 for x = 1 .

Pachacha [2.7K]

$f(x)=-3x-4$

Substitute x = 1 in the equation.

$f(1)=-3(1)-4\\f(1)=-3-4\\f(1)=-7$

Therefore, the answer is f(1) = -7

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3 years ago