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2 years ago

Find the decimal equivalent of ¾ ounce to the thousandths place

Mathematics

1 answer:

GalinKa [24]2 years ago

7 0

0.75

Explanation:

Every 1/4 is 25. If you want to calculate them, then you're going to need 1/4 to find 25. In some other cases, 25, can also be written as another decimal. Such as, 4/100.

100/4 is 25. For example:

Woah! You have 3/4 of a dollar. You're really saving up money fast!

This example means that the person has 75 cents.

For an ounce, that would mean 0.04 pounds.

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Then divide by two again to end up with 2 km in 15 mins.

You could alternatively divide by four from the beginning, but I find this easier.

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3 years ago

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1 year ago

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3 years ago

Find the exact value of cos 75 by using a sum or difference formula

anygoal [31]

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3 years ago

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by factoring the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0

2 years ago