Hey I'm probably too late but your answer would be 26-7i
Hope this helps :)
9514 1404 393
Answer:
8√3 ≈ 13.86 ft
Step-by-step explanation:
The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...
y = 1/(4p)x^2
y = 1/12x^2
The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.
For y=4, the corresponding value of x is ...
4 = 1/12x^2
48 = x^2
√48 = x = 4√3
Then the width of the searchlight opening is ...
2(4√3 ft) = 8√3 ft ≈ 13.86 ft
The solutions to the system of equations are (-2,-6) and (4,6)
<h3>How to determine the system of equations?</h3>
We have:
-2x + y = -2
![y = -\frac12x^2 + 3x + 2](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac12x%5E2%20%2B%203x%20%2B%202)
Next, we plot the graph of both functions.
From the attached graph, the equations intersect at (-2,-6) and (4,6)
Hence, the solutions to the system of equations are (-2,-6) and (4,6)
Read more about system of equations at:
brainly.com/question/21405634
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