Answer:
Here's one way to do it
Step-by-step explanation:
1. Solve the inequality for y
5x - y > -3
-y > -5x - 3
y < 5x + 3
2. Plot a few points for the "y =" line
I chose
\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}
x
−2
−1
0
1
2
y
−7
−2
3
8
13
You should get a graph like Fig 1.
3. Draw a straight line through the points
Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.
See Fig. 2.
4. Test a point to see if it satisfies the inequality
I like to use the origin,(0,0), for easy calculating.
y < 5x + 3
0 < 0 + 3
0 < 3. TRUE.
The condition is TRUE.
Shade the side of the line that contains the point (the bottom side).
And you're done (See Fig. 3).
Answer:
Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤ 
]
Another function is the inverse of f(x),
Now composite function of these functions will be,
![(fof^{-1})(x)=f[f^{-1}(x)]](https://tex.z-dn.net/?f=%28fof%5E%7B-1%7D%29%28x%29%3Df%5Bf%5E%7B-1%7D%28x%29%5D)
= ![[-6(\frac{\sqrt{x}+8}{6})-8]^{2}](https://tex.z-dn.net/?f=%5B-6%28%5Cfrac%7B%5Csqrt%7Bx%7D%2B8%7D%7B6%7D%29-8%5D%5E%7B2%7D)
= ![[-\sqrt{x}+8-8]^2](https://tex.z-dn.net/?f=%5B-%5Csqrt%7Bx%7D%2B8-8%5D%5E2)
= 
= x
Therefore,
Answer:
253,498.1?
Step-by-step explanation:
Answer: just simplify condense it then your answer will be log(16)
Answer:
The correct option is;
DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)
Step-by-step explanation:
Given that we have;
1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC
2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC
3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC
Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;
AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))
∴ (sin(m∠ADE)) = (sin(m∠ABC))
m∠ADE) = m∠ABC).
