Answer: 13.7 in²
<u>Step-by-step explanation:</u>
Area of Square:
A = s²
= 8²
= 64
Area of Circle:
A = π r²
= π (4)²
= 16π
≈ 50.3
Area of Square - Area of Circle:
64 - 50.3 = 13.7
58 I think (not sure though)
1. Brandi was driving 60mph down the highway. Ratio is 60/1. 60mi per 1 hr
2. Brandi bought 5 apples at the store and 6 oranges. The ratio of apples to oranges is 5:6 or 5 to 6.
3. Brandi has 3 sisters and 1 brother. Ratio of sisters to brothers is 3:1 or 3 to 1.
4. Brandi has 20 shirts and 10 pants in her closet. The ratio of shirts to pants is 20:10 or 20 to 10.
5. Brandi has 12 boys in her class and 13 girls. The ratio of boys to girls is 12:13 or 12 to 13
Hope this helps:)
Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)

A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
5.0000001.0000000
+
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