If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
2 answers:
The given function are
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>
<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>
As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>
<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>
As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>
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Answer:
Area of triangle ABC=7 square units
Area of triangle A'B'C'=7 square units
Step-by-step explanation:
Triangle ABC is the preimage of triangle A'B'C' under a reflection in the line x=0.
The two triangles are congruent so they have the same area.
We can calculate the area by counting the unit squares the triangle covered.
Each full box is 1 units square.
Each triangle covered
1 full box and 12 partially covered boxes.
Each partial box covered is 0.5 square units.
Therefore the area is
square units