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2 years ago

Who ever gets this question right is BRAINLIEST. Answer For 15 Points

Mathematics

1 answer:

stich3 [128]2 years ago

8 0

Answer:

ITS C:D pls give brainliest

Step-by-step explanation:

add all it equals C, 16.25

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CAN YOU GUYS HELP PLEASE, I HAVE A LIMIT ON THIS!!!!

lorasvet [3.4K]

Answer:

the 2nd choice

Step-by-step explanation:

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may i get braineist pls

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2 years ago

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A horizontal force of 480 n is applied to a stationary wooden box in one direction and a 600 n horizontal force is applied in th

maksim [4K]

Answer:

Step-by-step explanation:

In a static position, the sum of the forces is always 0.

so:

F1 = 480 N

F2 = -600 N

F3 = ?

F1 + F2 + F3 = 0

480 - 600 + F3 = 0

F3 = 120 N (the answer is positive, so the force acts in the same direction as F1)

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2 years ago

Write an expression for the sequence of operations described below.

emmasim [6.3K]

Answer:

8x10+m

Step-by-step explanation:

because of PEMDAS you multiply the 8x10 1st then add the product to m

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3 years ago

(50 POINTS) Math Inverse Functions please help

Afina-wow [57]

Answer:

See below.

Step-by-step explanation:

An inverse function has the x and y coordinates switched. For example, if a function has point (1, 3), then the inverse function has point (3, 1).

Let's find the ordered pairs of the inverse function. We take all the ordered pairs of the original function:

(1, 3), (7, 4), (8, 6), (9, y)

Now we switch x and y in each ordered pair to come up with the inverse function.

The inverse function has these ordered pairs:

(3, 1), (4, 7), (6, 8), (y, 9)

For a relation to be a function, a value used as an x-coordinate can appear only once.

The last ordered pair is (y, 9). For the inverse relation to be a function, y cannot be 3, 4, or 6.

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3 years ago

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Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your

Archy [21]

The value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Given the equation y=16- $x^{2}$ and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16- $x^{2}$ from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16- $x^{2}$

Find the integration of 16- $x^{2}$ .

=16x- $x^{3}/3$

Now find the value of integration from x=-1 to x=1.

=16(1)- $(1)^{3}/3$ -16(-1)- $(-1)^{3}/3$

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

#SPJ4

4 0

1 year ago