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postnew [5]
3 years ago
6

What is the least common multiple of 9 and 17?

Mathematics
1 answer:
Sav [38]3 years ago
7 0

As they are not divisible to each other, we can't reduce that and in that condition their LCM would be their product = 9* 17 = 153

SO YOUR ANSWER IS 153

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You multiply 1.75 by 35 then subtract by 100

4 0
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What is the measure of ABC?
MaRussiya [10]

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D i think

Step-by-step explanation:

3 0
2 years ago
which is the slope of a line that is perpendicular to the line that passes through the points (29, 24) and (3, 4)?
Nataliya [291]

Answer:

26/20

Step-by-step explanation:

y2-y1 divided by x2-x1

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3 0
3 years ago
Sam bought a kite that he could do stunts with for $52. If he
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Answer:

8.5%

Step-by-step explanation:

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5 0
3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

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If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
2 years ago
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