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Talja [164]
3 years ago
8

Find volume of cone z=sqrt(x^2+y^2) that is bounded with z=5 and z=7

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0
Convert to cylindrical coordinates first, using

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}

Then the volume is

\displaystyle\int_{\zeta=5}^{\zeta=7}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\zeta}r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
=\displaystyle\pi\int_{\zeta=5}^{\zeta=7}\zeta^2\,\mathrm d\zeta
=\dfrac{218\pi}3
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