Question

When a quadratic equation has no linear term (variable raised to the first power), the solution becomes simpler. What are the two possible solutions to 5x^2−15=0? Enter your two answers separated by a comma.

Answer 1

Answer: $-\sqrt{3},\ +\sqrt{3}$

Step-by-step explanation:

The given quadratic equation :_ $5x^2-15=0$

To solve this , we first add 15 on the both the sides of the above equation, we get

$5x^2-15+15=0+15\\\\\Rightarrow\ 5x^2=15$

Now, we divide both sides by 5, we get

$x^2=3$

Taking square roots on both the sides , we get

$x=\pm\sqrt{3}$

Hence, the two possible solutions = $-\sqrt{3},\ +\sqrt{3}$