3 years ago

Value of this problem?

1 answer:

5 0

$\frac{4^3\times4^{-1}\times5^{-2}}{4^4\times5^{-3}\times5^0}=\frac{4^{3-1}\times5^{-2}}{4^4\times5^{-3+0}}\\=\frac{4^{2}\times5^{-2}}{4^4\times5^{-3}}=4^{2-4}\times5^{-2-(-3)}\\=4^{-2}\times5^{1}=\frac{5}{4^2}\\=\frac{5}{16}$

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