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3 years ago

8

You have isolated a particular virus and have found that the amount of thymine present in its double stranded DNA is 23%. Based

on that knowledge, what can you predict to be the percentage of guanine present in the same sample?
23%
46%
27%
54%

1 answer:

telo118 [61]3 years ago

5 0

The Answer Is 27% . . . . . . . . . . . . . The dots are so I can post the answer, because without a long reply I can't answer.

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Answer:

Frequency of allele S is p $= 0.4939$

Frequency of allele C is q $= 0.666$

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Explanation:

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Number of individuals with curly hair $= 444$

Number of individuals with Wavy hair $= 312$

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

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$p^{2} = \frac{244}{1000} \\= 0.244$

$q^2$ represents the frequency of genotype "CC"

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Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

$p+q=1\\$

Substituting the values in above equation, we get -

$0.4939+0.666\neq 1$

hence, the population is not in Hardy-Weinberg equilibrium

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