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2 years ago

What's the area of a rectangle measuring 13 in. × 12 in.? A. 50 sq. in. B. 25 sq. in. C. 156 sq. in. D. 144 sq. in.

Mathematics

2 answers:

Pavlova-9 [17]2 years ago

8 0

the area of a rectangle is equale side a x side b 
13 in. × 12 in = 156 sq. in.

bixtya [17]2 years ago

6 0

The answer is C. 156 sq. in.

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3 years ago

The diagram shows a semi circle inside a rectangle of length 140m. the semi circle touches the rectangle at P, Q and R. Calculat

exis [7]

Answer: 250m

Step-by-step explanation:

Length of rectangle = 140m

Length of rectangle = diameter of semicircle = 140m

Therefore, Radius(r) = 140m / 2 = 70m

Perimeter of the shaded region:

Length of tangent at P + length of tangent at Q + shaded portion of arc(AB)

Length of tangent = diameter / 2

Length of tangent = 70m

Perimeter of a circle = 2πr = 2 × 22/7 × 70 = 440m

shaded portion = 440 / 4 = 110m

Therefore, perimeter of shaded portion equals

70m + 70m + 110m = 250m

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3 years ago

What is 7% of 300000000 and how do you work it out?

ArbitrLikvidat [17]

Answer:

21,000,000

Step-by-step explanation:

Divide 7 into 300000000

If you could subscribe to my friend penny_pg3d on yt that would be great

5 0

2 years ago

Read 2 more answers

Evaluate x+2.7 for x=-1.5

jonny [76]

Answer:

1.2

Step-by-step explanation:

First make -1.5 equal to 0.

We'll have to add 1.5, right?

So 1.5 is in 2.7.

So now its 0 + ? = ?

2.7 - 1.5 = 1.2

So 0 + 1.2 = 1.2

Hope this helped.

3 0

3 years ago

Find the distance CD rounded to the nearest tenth C=(10,-1) and D=(-6,3)

Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: $L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

point C can be info set 1: (10, -1) x₁ = 10 y₁ = -1

point D can be info set 2: (-6, 3) x₂ = -6 y₂ = 3

Substitute the information into the formula

$L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

$CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }$ Simplify inside each bracket

$CD = \sqrt{(-16)^{2}+(4)^{2} }$ Square the numbers

$CD = \sqrt{256+16 }$ Add inside the root

$CD = \sqrt{272}$ Enter into calculator

$CD = 16.5$ Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0

3 years ago