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Harrizon [31]
3 years ago
9

the math contest kids studied for 12 hours before their math competition. then katelyen studied for another x number of hours. w

rite an equation that represents the total number of hours (y) that Katelyen studied
Mathematics
1 answer:
faltersainse [42]3 years ago
8 0
12+x=y

Hope this helped! :)
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Find the length of side x in simplest radical form with a rational denominator.
Salsk061 [2.6K]
Answer: 5/2

Explanation:

According to 30-60-90 triangle rule:

The side opposite of 30 degree is equal to half of the hypotenuse and the hypotenuse here is 5 so therefore x = 5/2
7 0
3 years ago
What is the measure of x?
stealth61 [152]

Answer:

65⁰

Step-by-step explanation:

Take a look for the pict

Or

x+50⁰=115⁰

x= 115⁰-50⁰

x=65⁰

7 0
3 years ago
Suppose 21% of people own a dog. If you pick two people at random, then what is the probability that they both own a dog?​
Goshia [24]

Hello there i hope you are having a great day :) Your question: Suppose 21% of people own a dog. If you pick two people at random, then what is the probability that they both own a dog?​

1) 21% own a dog so you would do 21/100 = 0.21 this would equal the first person now the second person you would do 21/100 = 0.21

2) now you would multiply it so 0.21 x 0.21 = 0.0441 the that would be your answer.

Hopefully that helps you ❤

6 0
4 years ago
examples of addition of three fractions ( between 0-1) with a common denominator. IN STEPS ALL WORK, I need two examples.
disa [49]
Quizlet !! just saw this on there !!
5 0
3 years ago
Read 2 more answers
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least... 

<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>

<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>

<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>

<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>

<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>

<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>

<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>

<span>Now apply the Law of Sines to find the other two angles. </span>

<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>

<span>Two down, one to go... </span>

<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>

<span>So your three angles are: </span>

<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
8 0
3 years ago
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