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suter [353]
3 years ago
12

What is the original price if saidhari and she paid $75 and it was 1/4 off the price

Mathematics
1 answer:
Lelu [443]3 years ago
4 0
Let's set the original price as x.

1/4 off the original price would be

x-1/4x=3/4x

Set it equal to 75

3/4x=75
3x=300
x=100

The original price was $100.

Hope this helps!
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Find each of the following for ​
KATRIN_1 [288]
<h2>Answer:</h2>

(a)

          f(x+ h)=8x+8h+3  

(b)

            f(x+ h)-f(x)=8h          

(c)

             \dfrac{f(x+ h)-f(x)}{h}=8

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as :

              f(x)=8x+3

(a)

           f(x+ h)

We will substitute (x+h) in place of x in the function f(x) as follows:

f(x+h)=8(x+h)+3\\\\i.e.\\\\f(x+h)=8x+8h+3

(b)

       f(x+ h)-f(x)              

Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:

f(x+h)-f(x)=8x+8h+3-(8x+3)\\\\i.e.\\\\f(x+h)-f(x)=8x+8h+3-8x-3\\\\i.e.\\\\f(x+h)-f(x)=8h

(c)

           \dfrac{f(x+ h)-f(x)}{h}            

In this part we will divide the numerator expression which is obtained in part (b) by h to get:

           \dfrac{f(x+ h)-f(x)}{h}=\dfrac{8h}{h}\\\\i.e.\\\\\dfrac{f(x+h)-f(x)}{h}=8    

5 0
3 years ago
Consider in the figure below.
yawa3891 [41]

Here BD is perpendicular bisector

So

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\\ \tt\hookrightarrow UV=74+74=148

Apply Pythagorean theorem

\\ \tt\hookrightarrow BD^2=UD^2-UB^2=UD^2-VD^2

  • UD=VD=78=TD

\\ \tt\hookrightarrow TC^2=TD^2-CD^2

\\ \tt\hookrightarrow TC^2=78^2-30^2

\\ \tt\hookrightarrow TC^2=6084-900=5184

\\ \tt\hookrightarrow TC=72

6 0
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Step-by-step explanation:

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Scatter Plot
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Answer:

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