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3 years ago

Find mKML mKML= HURRYY!!!

Mathematics

2 answers:

Goryan [66]3 years ago

8 0

Answer:

42˚

Step-by-step explanation:

lys-0071 [83]3 years ago

8 0

Answer:

42°

Step-by-step explanation:

Theorem of isosceles triangle says that the two adjacent angles that are not connected by two congruent lines are congruent.

Simple words:

L is the angle connected by both lines with the "ticks"

So that means K and M are congruent

Since K = 42°

M = 42°

Fun fact: If the angle name is something like ABC, the angle is technically B, because B is the vertex.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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A coin is tossed 7 times . Which of the following represents the probability of the coin landing on tails all 7 times

Studentka2010 [4]

Answer:

○ C. $\frac{1}{64}$

Step-by-step explanation:

Using the formula $\frac{1}{2^{n}}$ , where <em>n</em> represents the number of tosses, substitute 7 in for <em>n</em> to get this:

$\frac{1}{64} = \frac{1}{2^{7}}$

I am joyous to assist you anytime.

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3 years ago

Find the y-intercept and slope for the graph below

egoroff_w [7]

I believe it is 2.5 if you need me to explain I can

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3 years ago

What is the difference? StartFraction 2 x 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x 5 Over x cubed minus 9

Fiesta28 [93]

The expression which is equivalent to the difference of the given algebraic fraction is,

$\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}$

<h3>What is the difference? </h3>

Difference is the mathematical operation in which the one number is subtract from another number.

To find the difference of two fraction numbers, we find the least common factor of denominator and write the all numbers as one fraction.

The given expression in the problem is,

$\dfrac{2x+5}{x^2-3x}-\dfrac{3x+5}{x^3-9x}-\dfrac{x+1}{x^2-9}$

Factorize the denominator of each term as,

$\dfrac{2x+5}{x(x-3)}-\dfrac{3x+5}{x(x-3)(x+3)}-\dfrac{x+1}{(x-3)(x+3)}$

Here, the least common factor of the denominators is x(x-3)(x+3), therefore, the expression can be written as,

$\dfrac{(x+3)(2x+5)-(3x+5)-(x)(x+1)}{x(x-3)(x+3)}\\\dfr\dfrac{2x^2+5x+6x+15-3x-5-x^2-x}{x(x-3)(x+3)}\\\dfr\dfrac{x^2+7x+10}{x(x-3)(x+3)}\\\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}$