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Licemer1 [7]
3 years ago
7

A triangular sail has a base length of 2.5 centimeters. The area of the sail is 3.75 square meters. How tall is the sail?

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

The area of any triangle = (1/2) x (length of the base) x (height)

2.5 centimeters  =  0.025 meter

The area of the sail is           (3.75) = (0.5) x (0.025) x (height)

Multiply each side by  2 :      (7.5) =            (0.025) x (height)

Divide each side by  0.025 :  (7.5)/(0.025) = height  =<em>  300 meters</em>

The situation is stupid, but the math is bullet-proof.


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Answer:

a) The cost of buying this car is of £6200.

b) The monthly payment is of £450.

Step-by-step explanation:

The cost of buying a car is given by:

cost = 12 X monthly payment + deposit

a) Find the cost of a car when the monthly payment is £350 and the deposit is £2000.

So

cost = 12*350 + 2000 = 4200 + 2000 = 6200

The cost of buying this car is of £6200.

b) The cost of another car is £8000. Find the monthly payment when the deposit is £2600.

Again, the formula is applied. So

cost = 12 X monthly payment + deposit

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Hey there!

The x-intercept is where the line crosses the x-axis. The x-axis is horizontal. It crosses the line three left from the origin, or (0,0). This is -3. The x-intercept is -3. The answer would be either B or C. The line never hits the y-axis, so the y-intercept is none. The answer is C.

I hope this helps!
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Mathematical induction, prove the following two statements are true
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Prove:
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Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
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That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
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We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
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Distribute the -2 and combine the fractions together,
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Combine like-terms,
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pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
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Answer:

Step-by-step explanation:

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