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3 years ago

11

Estimate 193.492 to the nearest hundredth

1 answer:

taurus [48]3 years ago

7 0

You find the hundredth, then look at the number beside it. 2 is less than 5 so the 2 makes the 9 stay the same. You get rid of the 2 and you are left with 193.49. So your answer is 193.49

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A rectangle has an area of 10x^2-29x-21 square units. Which of the following could represent the primeter of the rectangle in te

nata0808 [166]

Area=LW
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3 years ago

Trevon’s school is selling tickets to a fall musical. On the first day of ticket sales the school sold 13 adult tickets and 12 s

julsineya [31]

9514 1404 393

Answer:

adult: $7
student: $10

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively.

13a +12s = 211 . . . . . . ticket sales the first day

5a +3s = 65 . . . . . . . ticket sales the second day

Subtracting the first equation from 4 times the second gives ...

4(5a +3s) -(13a +12s) = 4(65) -(211)

7a = 49 . . . . . . . simplify

a = 7 . . . . . . . divide by 7

5(7) +3s = 65 . . . . substitute into the second equation

3s = 30 . . . . . . . subtract 35

s = 10 . . . . . . . divide by 3

The price of one adult ticket is $7; the price of one student ticket is $10.

7 0

3 years ago

Is it 5 or six units?

charle [14.2K]

I don't understand your question
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7 0

3 years ago

Read 2 more answers

Solve for a.<br> a^2=-3a+88

Sergio [31]

Answer:

$a=8,-11$

Step-by-step explanation:

$a^2=-3a+88$

$a^2+3a=88$

$a^2+3a-88=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-3\pm\sqrt{3^2-4(1)(-88)} }{2(1)}$

$x=\frac{-3\pm\sqrt{9+352} }{2}$

$x=\frac{-3\pm\sqrt{361} }{2}$

$x=\frac{-3\pm19 }{2}$

$x=-11$ and $x=8$

Therefore, the values of $a$ are 8 and -11.

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2 years ago

What is the solution to = n/4 -12.4?

aleksandr82 [10.1K]

Answer:

I need the rest of the question

Step-by-step explanation:

Sorry I want to help you but I cant unless there is a (example): 12+-3= n/4 -12.4

or a list of options to choose from like what will equal 6? A.2 B.3 C.100 D.9

if you give me the rest I can solve, thanks :)

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3 years ago