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andrew11 [14]
2 years ago
15

The probability that Brian buys a sandwich is 0.1. The probability that Brian gets the bus is 0.6. Assuming the events are indep

endent, what is the probability that Brian buys a sandwich and gets the bus?
Mathematics
2 answers:
Vsevolod [243]2 years ago
7 0

Answer:

Step-by-step explanation:

omeli [17]2 years ago
5 0

Answer:

6% chance

Step-by-step explanation:

I think it would be 0.1 * 0.6 which is 0.06

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{(-1, 4), (-1, 9), (-1, 15), (-1, 0)}
marishachu [46]

Answer:

domain is -1

range is {4, 9, 15, 0}

function: not a function

6 0
3 years ago
3. What is the solution to the system of equations?
olga55 [171]
I think the answer is B but i could be wrong
3 0
2 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
To make concrete it takes 8 parts crushed gravel, 7 parts water and 5 parts cement mix. A worker needs to make 220kg of concrete
Alika [10]
A) 8 + 7 + 5 = 20 parts
b) 220 kg ÷ 20 = 11
c) <span> 8 parts crushed gravel: 8 x 11 = 88 kg
     7 parts water: 7 x 11 = 77 kg
     5 parts cement: 5 x 11 = 55 kg</span>
8 0
2 years ago
I need help with that, if you can, plz. I ty it I think is a not sure
STALIN [3.7K]

Answer:

-5≤x <1

Step-by-step explanation:

sqrt( x+5) / sqrt(1-x)

The numerator must be greater than zero since it is a square root

sqrt(x+5) ≥0

Square each side

x+5≥0

x≥-5

The denominator must be greater than zero (the denominator cannot be zero)

sqrt(1-x)> 0

Square each side

1-x > 0

1>x

Putting these together

-5≤x <1

5 0
3 years ago
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