The only solution to |r+3|=1 is -2? true or false
2 answers:
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The first thing we must do for this case is to find the equation of the line.
We have then:
We choose an ordered pair:
Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5
The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
We have then:
We choose an ordered pair:
Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5
The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
An ellipse (oval shape) is expressed by the following equation:
where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).
We can find the foci by using
36 - 11 =
Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.
So the foci are (-5, 0) and (5, 0)
Hope this helps :)
We can find the foci by using
36 - 11 =
Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.
So the foci are (-5, 0) and (5, 0)
Hope this helps :)