Answer:
72,70,72, 71,71,70,69,72,69
I really didn't understand the question or what to do, but I tried.
Step-by-step explanation:
Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions 
and 
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 
shown in purple, then we can plot the second one 
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
It is definitely a reflection over the horizontal (x) axis, but i think the dilation is by 2
Answer:
Problem 9: -1/2
Problem 10: 1/5
Step-by-step explanation:
Problem 10: Label the given ln e^(1/5) as y = ln e^(1/5).
Write the identity e = e. Raise the first e to the power y and the second e to the power 1/5 (note that ln e^(1/5) = 1/5). Thus, we have:
e^y = e^(1/5), so that y = 1/5 (answer).
Problem 9: Let y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) 1 /2
Write out the obvious:
4 = 4
Raise the first 4 to the power y and raise the second 4 to the power (log to the base 4 of) 1 /2. This results in:
4^y = 1/2. Solve this for y.
Note that 4^(1/2) = 2, so that 4^(-1/2) = 1/2
Thus, y = -1/2
