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3 years ago

15

6x+7=4x+4y complete the missing value (_,4)

1 answer:

hodyreva [135]3 years ago

8 0

Answer:

x = 4.5

Step-by-step explanation:

6x+7=4x+4y

The first step is to simplify the equation by combining the x terms

Subtract 4x from each side

6x-4x +7 = 4x-4x+4y

2x+7 = 4y

We know the y value is 4

Substitute y=4 into the equation

2x+7 = 4(4)

2x+7 =16

Subtract 7 from each side

2x+7-7 =16-7

2x=9

Divide by 2

2x/2 =9/2

x= 4.5

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2 years ago

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2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

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Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

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$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

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3 years ago