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▹ Answer
<em>18</em>
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▹ Step-by-Step Explanation
- 10 + 7 = -3
-3 + 7 =4
4 + 7 = 11
11 + 7 = 18
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Answer:
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 4.1 - 0.07 = 4.03 pounds
The upper end of the interval is the mean added to M. So it is 4.1 + 0.07 = 4.17 pounds
Rounded to one decimal place
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut point with the y axis.
By definition, if two straight lines are parallel then their slopes are equal. Thus, the slope of the line sought will be 

We substitute the given point to find b:

Finally the line is:

Answer:

Answer:
E) b^2
Step-by-step explanation:
Solving the first equation for a, we get ...
a - b = 0
a = b . . . . . . add b to both sides
Now, the expression ab can be rewritten as
ab = bb = b^2 . . . . . . substitute b for a
Answer:
(a) The sample sizes are 6787.
(b) The sample sizes are 6666.
Step-by-step explanation:
(a)
The information provided is:
Confidence level = 98%
MOE = 0.02
n₁ = n₂ = n

Compute the sample sizes as follows:



Thus, the sample sizes are 6787.
(b)
Now it is provided that:

Compute the sample size as follows:

![n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%28z_%7B%5Calpha%2F2%7D%29%5E%7B2%7D%5Ctimes%20%5B%5Chat%20p_%7B1%7D%281-%5Chat%20p_%7B1%7D%29%2B%5Chat%20p_%7B2%7D%281-%5Chat%20p_%7B2%7D%29%5D%7D%7BMOE%5E%7B2%7D%7D)
![=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2.33%5E%7B2%7D%5Ctimes%20%5B0.45%281-0.45%29%2B0.58%281-0.58%29%5D%7D%7B0.02%5E%7B2%7D%7D%5C%5C%5C%5C%3D6665.331975%5C%5C%5C%5C%5Capprox%206666)
Thus, the sample sizes are 6666.