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jeyben [28]
3 years ago
10

Very confused on this.... have a test tomorrow

Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

Answer:

ln(5/256)

Step-by-step explanation:

Step 1, do the stuff in parenthesis:

1/5 (2ln5 + 3ln5) - 8ln2 = 1/5 (5ln5) - 8ln2

Step 2, remove parenthesis and simplify:

1/5 (5ln5) - 8ln2 = ln5 - 8ln2

Step 3, use this formula-

8*ln2 = ln2^8 = ln256

-to get:

ln5 - 8ln2 = ln5 - ln256

Step 4, use another formula:

ln(A) - ln(B) = ln(A/B), so the answer is ln(5/256) TADA!

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Your water bill consists of five parts: A base hookup fee of $32.50, a water fee of $0.03 per gallon of water, a sewer fee of $0
Taya2010 [7]

hi

You have to keep calm and to treat data as it come.  

<u>1 ) Start by constant fees :  </u>

hook up fees  is  32.50  and  trash collection fees are 35

so contant fees  :  32.50 +35 =  67.50  

2 )  Now we have to deal with variable fees which depend on how much water is used

water fees :  

0.03 per gallon, and we have  4 000 gallon, so  :  

0.03*4 000 = 120  

Sewer fees  :  

0.01  per gallon, and we have  4 000 gallon, so  :  

0.01  * 4000 = 40  

3 ) Total before taxation we have :  

67.50 +120 +40 =  227.5  

4)  Now we apply tax on the total before tax.

tax is  5 % , which mean you rise the "off tax " price by 5 percent.  

<u>To grow a number of  X % ,  you multiply by  1+  X/ 100 </u>

here  X = 5  so  the multiplicator is  :  1 + 5/100 = 1.05  

<u>So total of the bill is :   227.5 * 1.05 = 238.875  </u>

The water compagny is  probably going to round it up to 238.88

4 0
1 year ago
Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number
Radda [10]

Answer:

A. Y-68=-5(x-14)

Step-by-step explanation:

Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. write an equation for the situation

We find the equation using the point slope equation of a line. This is given as:

y - y1 = m(x-x1)

The slope intercept form will be

y = -5x + b

since the amount decreases by $5 per day...

Our slope is -5 so m=-5

We have a point (x1,y1) = (14, 68)

Hence, we have:

y-68 = -5(x-14)

Option A is correct

4 0
3 years ago
Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4
baherus [9]

Answer:

log_3(2x+15)=2  and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3

6 0
3 years ago
Read 2 more answers
) A watershed experiences a rainfall of 8 inches. What is the runoff volume when the curve number is 80
finlep [7]

Answer:

5.625 inches

Step-by-step explanation:

Given that:

Total Rainfall in inches (P) = 8 inches

The runoff volume (in inches) Q = ???

The curve number CN = 80

Recall that: The runoff volume can be calculated by using the formula:

Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}    for P > 0.2S

Q = 0                     for P < 0.2S

S = \dfrac{1000}{CN}-10

where:

curve number CN = 80

S = \dfrac{1000}{80}-10

S = 2.5 inches

Since the rainfall (P) is greater than 0.25

Then:

Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}  

Q = \dfrac{(8-0.2(2.5))^2}{(8+0.8(2.5))}

Q = \dfrac{(8-0.5)^2}{(8+2)}

Q = \dfrac{(7.5)^2}{(10)}

Q = \dfrac{(56.25)}{(10)}

Q = 5.625 inches

Thus, the runoff volume = 5.625 inches

4 0
3 years ago
What is the expression in simplest form (3x -2) - (4x +1)
zzz [600]

Answer:

Step-by-step explanation:

(3x -2) - (4x +1)

= 3x - 2 - 4x - 1

= - x - 3

4 0
3 years ago
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