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2 years ago

Question 95 pts

Mathematics

1 answer:

garri49 [273]2 years ago

5 0

The correct answer is “hasn’t” probably maybe

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Did I do this right?

exis [7]

No. For instance, let’s look at 1)
It’s asking you to find what x is when x/10 = 6

So, consider the equation x/10=6
Multiply both sides by 10, and your answer is 60.
Now do this for each one.

7 0

3 years ago

How much<br> lemonade will<br> each person get<br> if 4 people share <br> 1/2 gallon equally?

Charra [1.4K]

I’m pretty sure the answer would be 8 if u cut 4 in half 4 times

3 0

2 years ago

The next event requires each runner to jump 8 hurdles that are spaced 12.3 meters apart. If there are 15 meters from the startin

inessss [21]

The race is 111.6 m long.

8 hurdles spaced 12.3 m apart means 7 spaces that are 12.3 m in length; 7*12.3 = 86.1

Add to this the distance to the first hurdle and the distance from the last hurdle:
86.1+15+10.5 = 111.6 m

3 0

2 years ago

Plz plz help help help plz plz help plz

uranmaximum [27]

Answer:

since your adding to hours each time youll have 11, then the answer would be d the last one :)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A quadratic equation is shown below:

sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

$3x^{2}-11x+10=0$ has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

$\frac{d}{dx}(3x^{2}-11x+10)=6x-11$

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

$x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

$x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}$

6 0

3 years ago