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expeople1 [14]
3 years ago
6

Question 95 pts

Mathematics
1 answer:
garri49 [273]3 years ago
5 0
The correct answer is “hasn’t” probably maybe
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!!!!!!!!!!!!!51 POINTS!!!!!!!! MULTIPLE CHOICE!!!!!!!!!!! PLEASE HELP!!!!!!!!!!!!!!!
Alex777 [14]
First do 4.04 mil - 3.66 mil to get .38 mil (which is 380 thousand) then divide 380,000/10 to get answer J. 38,000. Hope this helped
3 0
3 years ago
Solve<br> y=-x2-2x-2<br> y=x-4
Free_Kalibri [48]

Step-by-step explanation:

y−x2+2x=−4y-x2+2x=-4 , y+x=2

5 0
3 years ago
17) Convert the number to scientific notation 0.00317
Masteriza [31]

Answer:

3.17x10^-3

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

6 0
3 years ago
Add these polynomials and simplify. Enter your response in standard form.
Travka [436]

Answer:

Step-by-step explanation: Your not the boss of me!!!!

6 0
3 years ago
Read 2 more answers
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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