The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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16/-8=-2
Whenever dividing a -negative number and +positive number= number will be always -
3 3/7 / 1 1/7= 24/7 *7/8= 3 ( Cross out 7 and 7, divide by 1). Cross out 8 and 24 and divide by 8) ( Also always flip over the second fraction only when dividing)
3 3/7= 24/7 because multiply the denominator and whole number. 3*7=21
Add 21 with the numerator (3)= 21+3=24
-12.2 / (-6.1)=2
Whenever dividing two - negative numbers= + positive number
-2 2/5 / 4/5= -12/5*5/4=-3 Cross out 5 and 5- divide by 5. Cross out 4 and -12, divide by 4
Answers:
- 2 = 16/-8=-2
3= 3 3/7 /( dividing )1 1/7= 3
2= -12.2 / (-6.1)=2
-3=-2 2/5 / ( dividing) 4/5=-3
it take him 90 hrs to plow 60 acres
The correct answer would be C
Hope this helped
Answer:
16
Step-by-step explanation:
4x3=12 tins of white paint
12+4=16 total tins
