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3 years ago

10

A rectangle has dimensions of 7ft by 4 ft . The rectangle is increased in size five times . How many times does the perimeter in

crease ? The area increase?

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

The perimeter increases by 5 times as well. The area increases by 25 times because you have to square the ratios

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1.) Any measure representing the center of a set of data arranged in a decreasing or increasing order of magnitude.

Marrrta [24]

Answer: The median is defined the measure of the central value when arranged in ascending or descending order of magnitude.
An average is a single number that represents the “middle” value of all the numbers in a list or set. There are three different types of average. These are called the mean, the median, and the mode.
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3 0

3 years ago

Can someone help me with this problem I put 20 points on it

shtirl [24]

Answer:

1.27 million Earth's.

Step-by-step explanation:

(1.4 x 10^18) / (1.1 x 10^12) = 1.27 x 10^6

3 0

3 years ago

Simplify the expression. −9(4 − 3j)

faltersainse [42]

Answer:

-36 + 27j

Step-by-step explanation:

−9(4 − 3j)

Distribute

-9 * 4 -9 * (-3j)

-36 + 27j

6 0

3 years ago

Read 2 more answers

What is the slope of a line that is perpendicular to the line shown.

sertanlavr [38]

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

$m=\frac{\Delta y}{\Delta x}$

where

$\Delta y = y_2-y_1$ is the increment along the y-direction

$\Delta x = x_2 - x_1$ is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

$m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}$

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

$m_2 = -\frac{1}{m_1}$

Using $m_1 = -\frac{4}{3}$ , we find that a line perpendicular to the line shown should have a slope of

$m_2 = -\frac{1}{-4/3}=3/4$

5 0

3 years ago

Can anyone help me with number 10?

34kurt

Do you still need help?

6 0

3 years ago