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3 years ago

2x^2-10x-132 factor completely

Mathematics

1 answer:

Grace [21]3 years ago

6 0

The value of X=11, -6

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Which pair of angles are an example of alternate exterior angles?

AleksAgata [21]

A. sorry if it’s wrong!!

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3 years ago

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Find the range of the dataset<br> 8,11,5,22,9,18,5,20

lakkis [162]

Answer: 17

Step-by-step explanation: The range of a data set is the difference between the largest and smallest numbers

In this data set, the largest number is 22 and the smallest number is 5 so the range of the data set will simply be 22 - 5 or 17.

So the range of this data set is 17.

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4 years ago

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HELP PLS! WILL MARK BRAINLIEST! Read each problem statement and decide if

pogonyaev

Answer:

The answer is in the web link

Step-by-step explanation:

1.) https://shsmrward.weebly.com/uploads/1/0/0/3/10037735/independentdependent_ak.pdf

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3 years ago

for the school play four rows of chairs are set up there are 22 chairs in each row how many chairs are in all

allsm [11]

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3 years ago

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Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

4 years ago