A = cross sectional area of the pipe. When the pressure is expressed in terms of the equivalent height of a column of that fluid, as is common with water, the friction loss is expressed as S, the "head loss" per length of pipe, a dimensionless quantity also known as the hydraulic slope.
6²/2(3) +4
6²=36
2(3)=6
So now we have
36/6 + 4 which is 6 + 4 which is 10.
Answer: It will about 1.88 hours or 1 hour 52.5 minutes to clean the stadium if they work together .
Step-by-step explanation:
Given : Time taken by Kevin to clean a stadium = 5 hours
Rate of work done by Kelvin =
Time taken by Chris to clean a stadium = 3 hours
Rate of work done by Chris =
Let t be the time taken by both of them to clean the stadium together.
According to the question , we have
Rate of work done together = Rate of work done by Kelvin+Rate of work done by Chris

hours
[∵ 1 hour = 60 minutes]
Hence, It will about 1.88 hours or 1 hour 52.5 minutes to clean the stadium if they work together .
The solution for b could really be any answers as long as when that number is divided by 4.3 it is less than 11.3
1 possible answer though could be 11.3
Because when 11.3 is divided by 4.3 it is less then 11.3
Sorry if I'm missing something and the answer is wrong!
Answer:
$1002
Step-by-step explanation:
The answer could not be submitted;
So, I added it as an attachment