Answer:
We accept H₀
p-value = 0,1618
Step-by-step explanation:
We are going to solve a one tail proportion-test ( right tail)
We assume Normal distribution
Sample population 1000
Political strategist to test wants to test:
Null hypothesis H₀ p = p₀ or p = 26 %
Alternate hypothesis Hₐ p > p₀ or p > 26%
We assume CI 90 % then
α = 10 % α = 0,1 and z score for α = 0,1 is critical value
z = 2,32 ( note 2,32 is z score for α = 0,1017 "good approximation")
To compute z(s)
z(s) = ( p -p₀ ) / √ p₀q₀/n
z(s) = ( 0,29 - 0,26 ) /√ 0,26*0,74/1000
z(s) = 0,03 / 0,014
z(s) = 2,14
We compare z(s) and z(c)
z(s) < z(c)
2,14 < 2,32
z(s) is in the acceptance region we accept H₀
The p-value for z(s) is from z-table
p-value = 0,1618
