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Setler79 [48]
3 years ago
14

You hit a tennis ball with an initial vertical velocity of 25 m/s. The ball leaves the tennis racket 2 meters above the ground,

h_o. How much time does your opponent have before the ball hits the ground on the other side of the net, h(t)? Use h(t) = -5t^2 + v_0t + h_0 where h(t) is the height of a tennis ball being hit h_0 is the initial height v_0 is the velocity in meters/second after time (t) in seconds
Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

here

Step-by-step explanation:

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Which best describes the strength of a model with an r-value of 0.29
olchik [2.2K]
The <u>correct answer</u> is:

It is not a very strong fit.

Explanation:

The r-value, or correlation coefficient, tells us how closely our model fits the data.

The r-values range from -1 to 1.  -1 is a perfect fit of a decreasing model; 1 is a perfect fit of an increasing model.  0 is no fit at all.

Since our r-value is 0.29, this is much closer to 0 than it is to 1 or -1; this means it is not a very strong fit.
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3 years ago
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In the statement 10 + 0 = 0 + 10 how would you describe the zero (0)?​
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The additive property of zero states that when you have any number and add zero to it, your answer will always equal the original number
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3 years ago
Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

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3 years ago
The sum of two numbers is twice their difference. the larger number is 6 more than twice the smaller. find the numbers.
soldi70 [24.7K]
Let the numbers be x and y; x being the larger number and y being the smaller.

Given,
 
x + y = 2* (x - y)

x + y = 2x - 2y

x = 3y

Also given,

x = 6 + 2y

3y = 6 + 2y

--- y = 6

Thus, x = 3y = 3*6 = 18.

Therefore, the numbers are 18 and 6.
7 0
3 years ago
Find the value of expression m(m-n) for m=3 and n=1<br><br><br> I need the ANSWER ASAP
Alex73 [517]

Answer:

6

Step-by-step explanation:

m = 3

n = 1

Equation

m(m - n)     Substitute the givens

Solution

3(3 -1 )        Evaluate what is inside the brackets.

3(2)      multiply

6

7 0
3 years ago
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