3 years ago

If x= eighth root of y and y= z^16 how is x proportionate to z ?

1 answer:

8 0

$x= \sqrt[8]{y}
\\ y = z^{16}

$

Plug "y" into the first equation.

$x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2$

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