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joja [24]
3 years ago
13

If x= eighth root of y and y= z^16 how is x proportionate to z ?

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
x= \sqrt[8]{y}
\\ y = z^{16}



Plug "y" into the first equation.

x =  \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2
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