If x= eighth root of y and y= z^16 how is x proportionate to z ?

1 answer:

8 0

$x= \sqrt[8]{y}
\\ y = z^{16}

$

Plug "y" into the first equation.

$x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2$

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balandron [24]

Answer:

146

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Point A(2, 125)

Point B(98, 15)

Step 2: Identify

A(2, 125) → x₁ = 2, y₁ = 125

B(98, 15) → x₂ = 98, y₂ = 15

Step 3: Find distance d

Substitute in coordinates [Distance Formula]: $\displaystyle d = \sqrt{(98-2)^2+(15-125)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(96)^2+(-110)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{9216+12100}$
[√Radical] Add: $\displaystyle d = \sqrt{21316}$
[√Radical] Evaluate: $\displaystyle d = 146$