3 years ago

If x= eighth root of y and y= z^16 how is x proportionate to z ?

1 answer:

8 0

$x= \sqrt[8]{y}
\\ y = z^{16}

$

Plug "y" into the first equation.

$x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2$

You might be interested in

Korolek [52]

Answer:

81 dollars

Step-by-step explanation:

5 0

3 years ago

nikitadnepr [17]

Uiixhvxjgxufzfubicxguc

3 0

2 years ago

Nuetrik [128]

Matt would be now 15

3 0

3 years ago

swat32

Answer:

(Graph shows variables conducted) - shows that 1 ,2, 5, 8, 11 - odd<

5 0

3 years ago

bearhunter [10]

Answer:

8.06

Step-by-step explanation:

Use the Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

The hypotenuse is always the slanted side, or c (x in this picture), but the other numbers can be interchanged. Doesn't matter.

Plug the numbers 4 and 7 into the formula.

$4^{2} +7^{2} =c^{2} \\$

Now evaluate them to get $c^2$

16+49=65

To get c, take the square root of 65

$\sqrt{65} = 8.06$

6 0

3 years ago