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Serga [27]
3 years ago
5

The mapping diagram shows a relation. What is the domain of the relation

Mathematics
2 answers:
kramer3 years ago
5 0
Instead of simply speaking navajo what did the code talkers create
Elenna [48]3 years ago
3 0

Answer:

Step-by-step explanation:

i think its b

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a coin is taken at random froma purse that contains one penny, 2 nickels, 4 dimes, and 3 quarters. let x be the value of the dra
algol [13]

Answer:

x = 12.6 pennies

Step-by-step explanation:

total number of coins = 1 + 2+ 4 + 3 = 10 coins

P(penny) =\dfrac{1}{10}

P(nickels) =\dfrac{2}{10}

P(dimes) =\dfrac{4}{10}

P(quarters) =\dfrac{3}{10}

hence average value of the coin

x = Penny x P(Penny) + nickel x P(nickel) + dimes x P(dimes) + quarters x P(quarters)

nickels  = 5 pennies dimes = 10 ; and quarters = 25 pennies

x = 1 \times \dfrac{1}{10} + 5\times \dfrac{2}{10} +10\times \dfrac{4}{10} +  25\times \dfrac{3}{10}

x = 0.1 + 1 + 4 + 7.5

x = 12.6 pennies

hence, the average pennies for the first draw is equal to x = 12.6 pennies

6 0
3 years ago
A yard is approximately 5.68 x 10-4 miles. How is this number expressed in standard decimal notation?
belka [17]

Answer:

C: 0.000568 miles

Step-by-step explanation:

Essentially, the exponent on the 10 is how many places to move the decimal point, and negative versus positive dictates whether to move it right or left respectively.

4 0
3 years ago
Read 2 more answers
Quick algebra problem, please show work!
cricket20 [7]
5/x^2-1^2 + 3/x+1
5/(x+1)(x-1) + 3/x+1
5+3(x-1)/(x+1)(x-1)
5+3x-3/(x+1)(x-1)
Final answer : 3x+2/(x+1)(x-1)
5 0
3 years ago
PLEASEEEEEE HELPPPPP!!
DaniilM [7]

Answer:

y-b+am/m

Step-by-step explanation:

y-b=m(x-a)

y-b=MX-ma

mx=y-b+ma

x=y-b+ma/m

4 0
3 years ago
What is the factorization of 121b4 − 49? (11b − 7)(11b − 7) (11b 7)(11b − 7) (11b2 − 7)(11b2 − 7) (11b2 7)(11b2 − 7)
Inessa05 [86]

The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).

The equation 121b⁴ − 49

To find the Factorization of 121b⁴ − 49.

<h3>What is the factor of a^2-b^2?</h3>

The factor of a^2-b^2 is  (a+b)(a-b)

We have write the given equation in the form of a^2-b^2

= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).

To learn more about the factor visit:

brainly.com/question/25829061

5 0
2 years ago
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