<span>The answer is 217000000000</span>
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
Answer:
i know one is 60%
Step-by-step explanation:
Answer:
D = 12.94 m
Step-by-step explanation:
Coordinates of first tree = A(0,8)
Coordinates of second tree = A(12,4)
We need to find the distance between the two trees. We can find it using distance formula for coordinates as follows :
We have, x₁ = 0, x₂ = 12, y₁ = 8, y₂ = 4
Now using distance formula,
So, the distance between the two trees is 12.64 m.
Answer:
Step-by-step explanation:
hello :
a(x) = 3x - 12 and b(x) = x-9, so
a[b(x)]=a(x-9) =3(x-9)-12
a[b(x)]=3x-9-12
a[b(x)]=3x+21
