The answer to this question is
B, (-infinity, -28]. We can get this answer by first multiplying each side of the inequality by 7. That would get rid of the fraction. When one does that, the result is d + 28

0. That means that d

-28. In interval notation, which is the notation the problem is asking us, that would be
(-infinity, -28], since d is all values less than -28 this includes infinity, but it also includes -28, so there is a ] around it. That means that the answer to this question is
B, (-infinity, -28].
Answer:
b y=9000(1+3.5)20
Step-by-step explanation:
y=a(1+r)t
yer welcome
Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2