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Karolina [17]
3 years ago
8

Why did or go put dynamite under his pancakes

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
To give it a little kick?
You might be interested in
Help! I need to know how to solve this
bagirrra123 [75]
Every triangle measures 180 degrees.
In order to get the answer you need to add every equation and set it equal to 180.

2x+4+2x-9+x=180
Combine like terms.
5x-5=180
Add 5 to the other side.
5x=185
Divide by 5.
x = 37

Now, plug 37 in for every x.
Angle A: 2(37)-9
Angle B: 2(37)+4
Angle C: 37

The measures are:
Angle A = 65
Angle B = 78
Angle C = 37

Hope this helps!
7 0
2 years ago
What is the length of side x? If necessary, round your answer to two decimal places. 19 12
Valentin [98]

Answer:

D. 14.73

Step-by-step explanation:

According to Pythagoras,

19^2 = 12^2 + x^2

x^2 = 19^2 - 12^2

x^2 = 361 - 144

x^2 = 217

x = \sqrt{217}

x = 14.73

5 0
3 years ago
I need help on this and the first person that answer this correctly gets a BRANLIST(answer if you know)​
irakobra [83]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (4,1) and (8,-3)?
Rus_ich [418]

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

  so (-3-1)/(8-4)

  -4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so    1=-1(4)+b

        1=-4+b

        1+4=b

so b= 5

therefore the equation is  y=-x+5   so d

8 0
3 years ago
Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
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