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77julia77 [94]
3 years ago
12

Helpppppppp meeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

The length of the shorter piece is 5\textrm{ ft}.

The length of the longer piece is 11\textrm{ ft}.

Step-by-step explanation:

The five-step method is GUESS method.

Given:

Length of steel beam, L=16\textrm{ ft}

Length of longer piece is 1 foot longer than twice the shorter one.

Unknown:

Length of longer and shorter pieces of beam.

Let the length of shorter piece be x feet.

Therefore, the length of longer beam is equal to 1+2x

Evaluate:

Sum of lengths of longer and shorter pieces of beam is equal to the total length of beam. So,

x+1+2x=16\\3x+1=16\\3x=16-1\\3x=15\\x=\frac{15}{3}=5

Substitute and Solve:

Now, we have, x=5.

Substitute 5 for x for the lengths of shorter and longer pieces and solve for each. This gives,

Length of shorter piece = x=5\textrm{ ft}

Length of longer piece = 1+2x=1+2(5)=1+10=11\textrm{ ft}

Therefore, the lengths of shorter and longer pieces are 5\textrm{ ft} and 11\textrm{ ft} respectively.

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<h3>Lucas and Zoe will both next visit their mother on 7th of May at the same time.</h3>

Step-by-step explanation:

<em>First</em><em>,</em><em> </em><em>find </em><em>the </em><em>first</em><em> </em><em>multiple </em><em>that </em><em>can </em><em>be </em><em>divisible </em><em>by </em><em>5</em><em> </em><em>and </em><em>8</em><em>:</em>

<em>4</em><em>0</em><em> </em><em>is </em><em>divisible </em><em>by </em><em>5 </em><em>and </em><em>8</em><em>.</em>

<em>Second</em><em>,</em><em> </em><em>find </em><em>the </em><em>days </em><em>in </em><em>April </em><em>and </em><em>subtract </em><em>7</em><em> </em><em>from </em><em>the </em><em>days:</em>

<em>April</em><em>=</em><em>3</em><em>0</em><em> </em><em>days</em><em>.</em>

<em>3</em><em>0</em><em>-</em><em>7</em><em>=</em><em> </em><em>2</em><em>3</em><em> </em><em>days</em><em>.</em>

<em>Finally,</em><em> </em><em>subtract </em><em>2</em><em>3</em><em> </em><em>from </em><em>4</em><em>0</em><em> </em><em>and </em><em>find </em><em>it </em><em>in </em><em>the </em><em>next </em><em>month</em><em>,</em><em> </em><em>which </em><em>is </em><em>May</em><em>:</em>

<em>4</em><em>0</em><em>-</em><em>2</em><em>3</em><em>=</em><em>1</em><em>7</em>

<em>Therefore</em><em>,</em><em> </em><em>they </em><em>will </em><em>both </em><em>next </em><em>visit </em><em>their </em><em>mother </em><em>on </em><em>the </em><em>7</em><em>t</em><em>h</em><em> </em><em>of </em><em>May.</em>

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